10x+x^2=336

Solution for 10x+x^2=336 equation:

10x+x^2=336

We move all terms to the left:

10x+x^2-(336)=0

a = 1; b = 10; c = -336;
Δ = b2-4ac
Δ = 102-4·1·(-336)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-38}{2*1}=\frac{-48}{2}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+38}{2*1}=\frac{28}{2}
=14
$